Integrating a Gaussian Pulse for Kinetic Energy Calculation

In summary, the conversation discusses the difficulty in evaluating a specific integral involving a Gaussian pulse traveling in an infinite string under tension. The kinetic energy is derived from the integral of the partial, but further simplification proves challenging. The use of u-substitution and integration by parts is attempted, but the error function may be useful in solving the integral. Eventually, the conversation comes to the realization that partial integration can be used to solve the integral easily.
  • #1
atqamar
55
0
I'm having a hard time evaluating this integral.

A Gaussian pulse [tex]\psi (y,t) = Ae^{-( \frac{y-ct}{a} )^2}[/tex] is traveling in an infinite string of linear mass density [tex]\rho[/tex], under tension [tex]T[/tex].

I know the Kinetic Energy is the integral of the partial: [tex]\frac{\rho}{2} \int_{-\infty}^{\infty} (\frac{\partial \psi}{\partial t})^2 dy[/tex]. I evaluate the partial, and this simplifies to [tex]\frac{\rho}{2} \int_{-\infty}^{\infty} (\frac{2c(y-ct)}{a^2} \psi)^2 dy[/tex].

I don't know where to proceed from here. I tried u-substitution, and integration by parts, with no success. I think the error function is useful in this, but we haven't covered this in the physics course yet.
 
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  • #2
Integral is of the form [itex]\int x^2 e^{-x^2}dx[/itex] notice that this is the same as [itex] \int x (x e^{-x^2})dx[/itex] where the term between brackets is easy to integrate. Now use partial integration.
 
  • #3
Oh stupid me. That wasn't tough at all. Thanks!
 

Related to Integrating a Gaussian Pulse for Kinetic Energy Calculation

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