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How do you arrive at this?I think its better you do by parts first.Then you may arrive at \(\displaystyle \int\frac{\sqrt{x}}{\sqrt{x}+1}dx\)
Edit : made a mistake earlier
[tex]\displaystyle \begin{align*} \int{ \ln{ \left( \sqrt{x} + 1 \right) } \, dx} &= \int{ 1 \cdot \ln{ \left( \sqrt{x} + 1 \right) } \, dx} \end{align*}[/tex]Hello
I am struggling with this integral:
\[\int \ln\left(\sqrt{x}+1 \right)\,dx\]
I tried integrating by parts (multiplying the integral by 1), however I got stuck with another integral I couldn't solve on the way
\[\int \frac{1}{\sqrt{x}+1}dx\]
Thanks !