- Thread starter
- #1

#### DreamWeaver

##### Well-known member

- Sep 16, 2013

- 337

\(\displaystyle \text{Li}_{2m+1}(e^{-\theta})=\frac{2}{\pi}\int_0^{\pi /2}\text{Cl}_{2m+1}(\theta \tan x)\, dx\)

**NB. You're unlikely to find this is any books... I worked it out a while back, and haven't seen it anywhere else. That said, it's actually a lot easier than it looks...**