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[SOLVED] inequality solve (x+1)/6<x-(3x-2)/4

karush

Well-known member
Jan 31, 2012
2,648
Screenshot_20190908-095501_Gallery.jpg
Ok a student sent this to me yesterday so want to answer without too many steps

I think the first thing to do is multiply every
term by 12

$2(x+1)<12x-3(3x-2)$
Expanding
$2x+2<12x-9x+6$
 
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skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
639
That’s fine.
 

karush

Well-known member
Jan 31, 2012
2,648
That’s fine.
$\dfrac{x+1}{6}<x-\dfrac{3x-2}{4}$
Expanding
$2x+2<12x-9x+6$
Combine like terms
$2x+2<3x+6$
Subtract 2x from both sides
$2<x+6$
Subtract 6 from both sides
$-4<x$

Hopefully no typos

Looks like answer a.
 
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