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anemone
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Let $x, y$ be real numbers such that $9x^2+8xy+7y^2 \le 6$.
Show that $7x+12xy+5y \le 9$.
Show that $7x+12xy+5y \le 9$.
anemone said:Let $x, y$ be real numbers such that $9x^2+8xy+7y^2 \le 6$.
Show that $7x+12xy+5y \le 9$.---(2)
anemone said:Let $x, y$ be real numbers such that $9x^2+8xy+7y^2 \le 6$.
Show that $7x+12xy+5y \le 9$.
The inequality challenge is a mathematical problem that involves finding a range of values for two variables that satisfy a given inequality.
The inequality in this challenge is 7x+12xy+5y ≤ 9. This means that the sum of 7 times x, 12 times the product of x and y, and 5 times y must be less than or equal to 9.
The variables in this inequality are x and y. They can represent any real numbers that satisfy the given inequality.
The solution to this inequality challenge is the set of all possible values for x and y that satisfy the given inequality. This can be represented graphically as a shaded region on a coordinate plane, or algebraically as a set of ordered pairs.
Some strategies for solving this inequality challenge include graphing the inequality on a coordinate plane, substituting different values for x and y to see if they satisfy the inequality, and using algebraic techniques such as factoring and solving for a specific variable.