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randomkent
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Homework Statement
Q5. A 1500kg car is traveling east @ 15.0m/s, when it crashes into a 2500kg truck traveling in the same direction @ 12m/s. The car has a velocity of 13m/s affter the collision. Assuming this is an inelastic collision, determine:
a) speed of the truck just after the collision
b) how much kinetic energy is lost during the collision. Into what is this KE converted?
Homework Equations
m1u1 + m1u2 = m1v2 + m1v2
m1u1 + m1u2 = Vf(m1 + m2)
0.5mu^2 + 0.5mu^2 ≠ 0.5mv^2 + 0.5mv^2
The Attempt at a Solution
This is a question from a past exam paper, and I need to know this for my upcoming exam. The solutions page uses m1u1 + m1u2 = m1v2 + m1v2 for part a to get 13.2. They then used this info to get 4200J (lost) as heat and sound for part b.
From my understanding, the answer is already given (13); because aren't inelastic collisions meant to move at the same speed? Since they are moving at different speeds it must actually be ELASTIC, but then the answer is already there and part b would be invalid because no KE would be lost... The only thing I can think of is the fact that it says JUST AFTER the collision, but still the car and truck should stick together and move at the same speed, right? m1u1 + m1u2 = Vf(m1 + m2) couldn't be used because it says the car after is 13m/s; and if they stick together they would both be @ 13.125m/s to conserve momentum...