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12boone
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Homework Statement
A bullet is fired vertically into a 1.20 kg block of wood at rest directly above it. If the bullet has a mass of 24.0g and a speed of 540 m/s , how high will the block rise after the bullet becomes embedded in it?
Homework Equations
1/2mv^2+mgh=1/2mvf^2+mgh
mv=mvf
The Attempt at a Solution
I know that for this i must use momentum to find the final v which would be
mV=(m+M)V'
then i use that V' to find height
1/2mV'^2=(m+M)gh
I solved this and I got an answer of 413 meters this is wrong. I do not know what I am doing wrong.