- #1
e.chaniotakis
- 80
- 3
Hello!
I have a question concerning the relation of the index of refraction of a material with E/M wave frequency.
If we take the classical Feynman approach, we can envision the material as a series of atoms, with electrons bound with springs to the nuclei.
Let the natural frequencies of the oscillators be called ω0 and the electric field of the wave be E=Eo*e-iωt.
The E/M wave forces the electron to oscillate with frequency ω.
If we solve the differential equation, we will find:
y(t) = (q/m)*[Eo*e-iωt]/[(ωο2-ω2) ]
(we consider the damping infinitessimal).
The polarization of the material can be given from :
P=χeE
P=qy(t)
→ P = E*xe = Ε*[Nq2/m]*[1/{ωο2-ω2}]
/* N=nr of electrons per unit volume with natural frequency ω0 */
Τhe permitivity ε is given by:
ε=ε0*(1+χe) =
ε=ε0*(1+[Nq2/m]*[1/{ωο2-ω2}])
The index of refraction is given by:
n=sqrt(ε*μ)/sqrt(ε0*μ0) = ...
n= 1+{Nq2/2mε0}*{1/(ω02-ω2}
For ω<<ω0,
n=1+(Nq2/2mε0)*{ [1/ω02]+[1/ω04]*ω2] }
n=1+A+Bω2
This is the actual derivation of the dispersion formula.
Now, if I wanted to "popularize" the effect to a high school student, how should I phrase it?
My idea was something like the following:
When a photon enters the material, it forces the electrons to oscillate. If ω<ω0, as ω increases , the amplitude increases until it reaches resonance.
As the amplitude increases, the probability of a photon to interact with an electron increases since there are more "meeting points" for a photon and an electron .
Thus, effectively there will be more Rayleigh scattering processes per unit length, and the photon will "take more time" to pass through the material.
Thus its speed effectively decreases or the index of refraction increases.
Is this "popularization" correct?
Thank you
I have a question concerning the relation of the index of refraction of a material with E/M wave frequency.
If we take the classical Feynman approach, we can envision the material as a series of atoms, with electrons bound with springs to the nuclei.
Let the natural frequencies of the oscillators be called ω0 and the electric field of the wave be E=Eo*e-iωt.
The E/M wave forces the electron to oscillate with frequency ω.
If we solve the differential equation, we will find:
y(t) = (q/m)*[Eo*e-iωt]/[(ωο2-ω2) ]
(we consider the damping infinitessimal).
The polarization of the material can be given from :
P=χeE
P=qy(t)
→ P = E*xe = Ε*[Nq2/m]*[1/{ωο2-ω2}]
/* N=nr of electrons per unit volume with natural frequency ω0 */
Τhe permitivity ε is given by:
ε=ε0*(1+χe) =
ε=ε0*(1+[Nq2/m]*[1/{ωο2-ω2}])
The index of refraction is given by:
n=sqrt(ε*μ)/sqrt(ε0*μ0) = ...
n= 1+{Nq2/2mε0}*{1/(ω02-ω2}
For ω<<ω0,
n=1+(Nq2/2mε0)*{ [1/ω02]+[1/ω04]*ω2] }
n=1+A+Bω2
This is the actual derivation of the dispersion formula.
Now, if I wanted to "popularize" the effect to a high school student, how should I phrase it?
My idea was something like the following:
When a photon enters the material, it forces the electrons to oscillate. If ω<ω0, as ω increases , the amplitude increases until it reaches resonance.
As the amplitude increases, the probability of a photon to interact with an electron increases since there are more "meeting points" for a photon and an electron .
Thus, effectively there will be more Rayleigh scattering processes per unit length, and the photon will "take more time" to pass through the material.
Thus its speed effectively decreases or the index of refraction increases.
Is this "popularization" correct?
Thank you