- Thread starter
- #1

**Two independent events have probabilities 0.1 and 0.3. What is the probability that at least one of**

the events occurs?

the events occurs?

I have an answer of .37, when I looked up the solution it is the same value but it was solved another way. I was just wondering if my logic would work.

Find $P(a \cup b) = P[a] + P

**- P[a \cap b]$**

So I have P[a] and P

So I have P[a] and P

**, and I can find $P[a \cap b]$ from independence I can say that;**

$P[a \cap b]$ = P[a]*P$P[a \cap b]$ = P[a]*P

**, correct?**

Or is the only way that I can solve it which is easier then my approach,

1-P[neither event]

1-P(1-a)*P(1-b)

But I do not feel that this would be the first way that would pop into my mind.Or is the only way that I can solve it which is easier then my approach,

1-P[neither event]

1-P(1-a)*P(1-b)

But I do not feel that this would be the first way that would pop into my mind.