- #1
UrbanXrisis
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If a ball at 5m/s struck two stationary balls and it is repelled back at -3m/s at an angle of 15 degrees, what would be the velocity of ball #2 if ball #1 traveled at 1m/s and 10 degrees from the normal?
Treat x and y components of momentum separately. (Call the original direction the x-axis.)UrbanXrisis said:but how do I take the angles into account?
A 2D collision is a type of collision that occurs in a two-dimensional space, where two objects collide and exchange energy and momentum.
The velocity of a ball after a 2D collision is calculated using the principles of conservation of momentum and conservation of energy. The equations used depend on the type of collision (elastic or inelastic) and the initial velocities of the objects involved.
An elastic collision is a type of collision where the total kinetic energy of the system is conserved. In other words, the objects collide and bounce off each other without any loss of energy.
An inelastic collision is a type of collision where some of the kinetic energy is lost during the collision. The objects involved may stick together or deform upon impact, resulting in a decrease in total kinetic energy.
The velocities of balls after a 2D collision can be affected by the masses, initial velocities, and types of collisions (elastic or inelastic) of the objects involved. Other factors such as friction and external forces may also play a role in the final velocities.