- #1
FrankJ777
- 140
- 6
Hey guys. I'm trying to comprehend the TEmn EM fields in wave guides. I've gone through the derivation, using Pozar's microwave textbook, and for the most part it's straight forward. I am having a hard time though determining what the effect of the imaginary factor in the field equations are.
Here is the simplest case, a TE10 wave propagating in the z direction, with a picture of the waveguide dimentions and the E field as I would imagine it to be.
The E and H fields are given as:
E[itex]_{y}[/itex] = [itex]\frac{-jωμm\pi}{k^{2}a}[/itex] A sin[itex]\frac{mx\pi}{a}[/itex] e[itex]^{-jβz}[/itex]
H[itex]_{x}[/itex] = [itex]\frac{jβm\pi}{k^{2}a}[/itex] A sin[itex]\frac{mx\pi}{a}[/itex] e[itex]^{-jβz}[/itex]
I understand there is a dependency on z from the e[itex]^{-jβz}[/itex] factor.
I also understand there is a time and frequency dependancy (not shown) from e[itex]^{jωt}[/itex] factor.
But what I'm really trying to understand is, how does the factor, [itex]\frac{-jωμm\pi}{k^{2}a}[/itex] , effect the fields?
I'm not sure how I should tread the imaginary factor in this case.
Thanks a lot.
Here is the simplest case, a TE10 wave propagating in the z direction, with a picture of the waveguide dimentions and the E field as I would imagine it to be.
The E and H fields are given as:
E[itex]_{y}[/itex] = [itex]\frac{-jωμm\pi}{k^{2}a}[/itex] A sin[itex]\frac{mx\pi}{a}[/itex] e[itex]^{-jβz}[/itex]
H[itex]_{x}[/itex] = [itex]\frac{jβm\pi}{k^{2}a}[/itex] A sin[itex]\frac{mx\pi}{a}[/itex] e[itex]^{-jβz}[/itex]
I understand there is a dependency on z from the e[itex]^{-jβz}[/itex] factor.
I also understand there is a time and frequency dependancy (not shown) from e[itex]^{jωt}[/itex] factor.
But what I'm really trying to understand is, how does the factor, [itex]\frac{-jωμm\pi}{k^{2}a}[/itex] , effect the fields?
I'm not sure how I should tread the imaginary factor in this case.
Thanks a lot.