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- Thread starter Fermat
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- Thread starter
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- Mar 10, 2012

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This is not true.Given 2 subspaces and a linear operator, is the image of the direct sum of the subspaces equal to the union of the images under the operator?

Thanks

For a counterexample:

Let $V=\mathbb R^2$ and $X=\{(x,0):x\in\mathbb R\}$ and $Y=\{(0,y):y\in\mathbb R\}$.

Then $X$ and $Y$ are subspaces of $V$.

Let $I$ be the identity operator on $V$.

You can see that $I(X\oplus Y)\neq I(X)\cup I(Y)$.

To make your statement true you can have:

Given 2 subspaces of a vector space $V$ and a linear operator on $V$, the image of the direct sum of the subspaces is equal to the