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[SOLVED] If z = -3+4i...(related vectors)

Raerin

Member
Oct 7, 2013
46
If z = -3+4i, determine the following related complex numbers

a) vector z
b) 3(vector z)
c) 1/z
d) 1/(vector z)
e) |z|
f) |vector z|
g) (vector z)/(|z|^2)

I'm not sure if it's a vector, but the z has a short line above it when I say "vector z."
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Re: If z = -3+4i...

The line over a complex number refers to its conjugate. If $z=a+bi$, then $\overline{z}=a-bi$. Are you familiar with the other notations?
 

Raerin

Member
Oct 7, 2013
46
Re: If z = -3+4i...

The line over a complex number refers to its conjugate. If $z=a+bi$, then $\overline{z}=a-bi$. Are you familiar with the other notations?

Nope :( but |z| refers to the length of it? So it'll be the radius of a circle?
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Re: If z = -3+4i...

Yes, $|z|$ refers to the magnitude, which is given by:

\(\displaystyle |z|=\sqrt{a^2+b^2}\)

So, what do you find for the magnitude of the given complex number?
 

Raerin

Member
Oct 7, 2013
46
Re: If z = -3+4i...

Yes, $|z|$ refers to the magnitude, which is given by:

\(\displaystyle |z|=\sqrt{a^2+b^2}\)

So, what do you find for the magnitude of the given complex number?
Ahh, I see, so |z| would be 5.

Also, when 1 is divided by z, is it the same as dividing 1 with...5, let's say?
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Re: If z = -3+4i...

Yes, correct on both counts. (Sun)

So, what about parts b) and c)?
 

Raerin

Member
Oct 7, 2013
46
Re: If z = -3+4i...

Yes, correct on both counts. (Sun)

So, what about parts b) and c)?
Okay, I understand everything now. Thanks for your help!
 

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,901
Re: If z = -3+4i...

Hi Raerin, welcome to MHB! :)

Also, when 1 is divided by z, is it the same as dividing 1 with...5, let's say?
I'd like to add a bit of nuance here.

\begin{aligned}
\frac 1 z &= \frac 1 {-3+4i} \\
&= \frac 1 {-3+4i} \cdot \frac {-3-4i} {-3-4i} \\
&= \frac {-3-4i} {(-3+4i)(-3-4i)} \\
&= \frac {-3-4i}{(-3)^2-(4i)^2} \\
&= \frac {-3-4i}{9+16} \\
&= \frac 1 {25} (-3-4i)
\end{aligned}
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Re: If z = -3+4i...

Hi Raerin, welcome to MHB! :)



I'd like to add a bit of nuance here.

\begin{aligned}
\frac 1 z &= \frac 1 {-3+4i} \\
&= \frac 1 {-3+4i} \cdot \frac {-3-4i} {-3-4i} \\
&= \frac {-3+4i} {(-3+4i)(-3-4i)} \\
&= \frac {-3-4i}{(-3)^2-(4i)^2} \\
&= \frac {-3-4i}{9+16} \\
&= \frac 1 {25} (-3-4i)
\end{aligned}
Yes, I was mistakenly referring to \(\displaystyle \frac{1}{|z|}\). Good catch! (Yes)