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#### karush

##### Well-known member

- Jan 31, 2012

- 2,928

$(–1, 4)$ and $(3, –1)$.

Give answer in the form \(\displaystyle r = p + td\)

*,*

where \(\displaystyle t \in {R}\)

position vector would be \(\displaystyle (3, -1) = p\)

direction vector would be (3+1,-1-4) = (4,-5) = d

so \(\displaystyle r=(3,-1)+t(4,-5)\)