# [SOLVED]IBV6 Find a vector equation of the line passing through (–1, 4) and (3, –1). in form r = p + td

#### karush

##### Well-known member
Find a vector equation of the line passing through
$(–1, 4)$ and $(3, –1)$.
Give answer in the form $$\displaystyle r = p + td$$,
where $$\displaystyle t \in {R}$$

position vector would be $$\displaystyle (3, -1) = p$$

direction vector would be (3+1,-1-4) = (4,-5) = d

so $$\displaystyle r=(3,-1)+t(4,-5)$$

Staff member
Looks good!