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[SOLVED] IBV6 Find a vector equation of the line passing through (–1, 4) and (3, –1). in form r = p + td

karush

Well-known member
Jan 31, 2012
2,724
Find a vector equation of the line passing through
$(–1, 4)$ and $(3, –1)$.
Give answer in the form \(\displaystyle r = p + td\),
where \(\displaystyle t \in {R}\)

position vector would be \(\displaystyle (3, -1) = p\)

direction vector would be (3+1,-1-4) = (4,-5) = d

so \(\displaystyle r=(3,-1)+t(4,-5)\)
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Looks good! :D