- #1
Agent_J
- 13
- 0
Find the center and radius of the circle
16x^2 + 16y^2 + 8x + 32y + 1 = 0
So first i simplified the equation by taking out the 16
so i got:
16 (x^2 + 1/2x + y^2 + 2y) = -1
16 (x^2 + 1/2x + 1/16) + 16 (y^2 + 2y + 1) = -1 + 1 + 1
16 (x + 1/4)^2 + 16 (y + 1)^2 = 1
Center = (-1/4, -1)
Radius = 1
Are my calculations correct? Do I need to take out the 16 in my equation?
16x^2 + 16y^2 + 8x + 32y + 1 = 0
So first i simplified the equation by taking out the 16
so i got:
16 (x^2 + 1/2x + y^2 + 2y) = -1
16 (x^2 + 1/2x + 1/16) + 16 (y^2 + 2y + 1) = -1 + 1 + 1
16 (x + 1/4)^2 + 16 (y + 1)^2 = 1
Center = (-1/4, -1)
Radius = 1
Are my calculations correct? Do I need to take out the 16 in my equation?