- #1
mcintyre_ie
- 66
- 0
Hey,
I’d really appreciate some help with these problems. I know it seems like I’m probably just asking you to do my entire assignment for me – but I assure you, this is (sadly) just a tiny piece of what I’ve got to do. I’ve attempted all of them, and still not coming up with any solutions. I’d appreciate any help you can give:
Q.2 (a) x^2 + 2x + p is a factor of x^3 + ax^2 + bx + c. Show that c = (a – 2)(b – 2a + 4).
What I’ve done so far:
I divided the (^2 + 2x + p) into (x^3 + ax^2 + bx + c), hoping to be able to equate the remainder to zero and then find c. I got c = 2x^2 + 2ax – bx + px + pa. I don’t know whether this is right (probably isn’t) or what I should do next.
Q.6 (c) Find the co-ordinates of the minimum point of the function f: x xe^x – 4e^x.
I differentiated xe^x – 4e^x and equated it to zero, getting an answer of x=3. I then subbed this back into xe^x – 4e^x and got a co-ordinate of (3 , 3e^3 – 4e^3). This doesn’t seem very right to me… any ideas?
These two are the only ones I’ve got at the minute, but I’m sure I’ll be back with more after I’ve attempted the rest a few more times.
PS - Great new forum layout, haven't had a chance to visit since the redesign.
I’d really appreciate some help with these problems. I know it seems like I’m probably just asking you to do my entire assignment for me – but I assure you, this is (sadly) just a tiny piece of what I’ve got to do. I’ve attempted all of them, and still not coming up with any solutions. I’d appreciate any help you can give:
Q.2 (a) x^2 + 2x + p is a factor of x^3 + ax^2 + bx + c. Show that c = (a – 2)(b – 2a + 4).
What I’ve done so far:
I divided the (^2 + 2x + p) into (x^3 + ax^2 + bx + c), hoping to be able to equate the remainder to zero and then find c. I got c = 2x^2 + 2ax – bx + px + pa. I don’t know whether this is right (probably isn’t) or what I should do next.
Q.6 (c) Find the co-ordinates of the minimum point of the function f: x xe^x – 4e^x.
I differentiated xe^x – 4e^x and equated it to zero, getting an answer of x=3. I then subbed this back into xe^x – 4e^x and got a co-ordinate of (3 , 3e^3 – 4e^3). This doesn’t seem very right to me… any ideas?
These two are the only ones I’ve got at the minute, but I’m sure I’ll be back with more after I’ve attempted the rest a few more times.
PS - Great new forum layout, haven't had a chance to visit since the redesign.