- #1
Vane9488
- 4
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The question: A grasshopper makes four jumps. The displacement vectors are (1) 27.0 cm due west (2) 23.0 cm, 35.0[tex]^{o}[/tex] due south of west (3) 28.0 cm, 55.0[tex]^{o}[/tex] south of east and (4) 35.0 cm, 63.0 [tex]^{o}[/tex] north of east. Find the magnitude and direction of the resultant displacement. Express the direction with respect to due west.
Vector magnitude direction x component y component
(1) 27.0 cm 0 [tex]^{o}[/tex] 27 cos 0[tex]^{o}[/tex] 27 sin 0[tex]^{o}[/tex]
(2) 23.0 cm 35.0 [tex]^{o}[/tex] 23 cos 35[tex]^{o}[/tex] 23 sin 35[tex]^{o}[/tex]
(3) 28.0 cm 55.0 [tex]^{o}[/tex] 28 cos 55[tex]^{o}[/tex] 28 sin 55[tex]^{o}[/tex]
(4) 35.0 cm 63.0 [tex]^{o}[/tex] 35 cos 63[tex]^{o}[/tex] 35 sin 63[tex]^{o}[/tex]
r= resultant variable
I add all of the x components and I get 62 cm.
I add all of the y components and I get 49.5 cm.
r=[tex]\sqrt{x^{2}+ y^{2}}[/tex]
r=111.5 cm
the direction i get 38.6[tex]^{o}[/tex].
Thats not the right answer! Please help!
Vector magnitude direction x component y component
(1) 27.0 cm 0 [tex]^{o}[/tex] 27 cos 0[tex]^{o}[/tex] 27 sin 0[tex]^{o}[/tex]
(2) 23.0 cm 35.0 [tex]^{o}[/tex] 23 cos 35[tex]^{o}[/tex] 23 sin 35[tex]^{o}[/tex]
(3) 28.0 cm 55.0 [tex]^{o}[/tex] 28 cos 55[tex]^{o}[/tex] 28 sin 55[tex]^{o}[/tex]
(4) 35.0 cm 63.0 [tex]^{o}[/tex] 35 cos 63[tex]^{o}[/tex] 35 sin 63[tex]^{o}[/tex]
r= resultant variable
I add all of the x components and I get 62 cm.
I add all of the y components and I get 49.5 cm.
r=[tex]\sqrt{x^{2}+ y^{2}}[/tex]
r=111.5 cm
the direction i get 38.6[tex]^{o}[/tex].
Thats not the right answer! Please help!