- #1
uzman1243
- 80
- 1
HW Template missing as it was moved from another forum
I don't understand how they got the "position of individual forces".
For F1, I'm guessing they used a pressure diagram and that's why it's 2/3 from the tip of the triangle. But why wouldn't the force act on the centroid for this square section (thus its 3.5/2)?
But for position of F2 (y2), they used the equation. Can you explain this?