How to start this off ( chem ?)

[2slowtogofast]

in order to plate a steel part that has a surface area of 200 in^2 with a 0.002 in thick layer of nickle, how many atoms of nickle are required

not looking for an answer i just need help on what to do. i know how to find how many atoms of somthing when given the weight. just not sure what to do in this case. i was thinking find the volume by 200 * 0.002 then using the density of nickle to find the mass and then go from there. But the numbers i was getting didt seem right.

 

[CompuChip]

Your approach looks correct. Can you show us the calculations?

 

[Blueshift5]

To start off, you will need to convert the surface area of the steel part from square inches to square meters. This can be done by dividing the surface area by 1550 (since 1 square inch = 0.00064516 square meters). This will give you the surface area in square meters.

Next, you will need to find the volume of the nickel layer. This can be done by multiplying the surface area in square meters by the thickness of the layer in meters (0.002 inches = 0.0000508 meters). This will give you the volume of the nickel layer in cubic meters.

Now, you can use the density of nickel to find the mass of the nickel layer. The density of nickel is 8.908 g/cm^3 or 8.908*10^6 g/m^3. Multiply this density by the volume you calculated earlier to get the mass of the nickel layer in grams.

Finally, you can use the atomic mass of nickel (58.6934 g/mol) to calculate the number of atoms required. Divide the mass of the nickel layer by the atomic mass to get the number of moles. Then, multiply the number of moles by Avogadro's number (6.022*10^23 atoms/mol) to get the total number of atoms required.

In summary, the steps to start off would be:
1. Convert the surface area of the steel part from square inches to square meters.
2. Calculate the volume of the nickel layer in cubic meters.
3. Use the density of nickel to find the mass of the nickel layer in grams.
4. Use the atomic mass of nickel to calculate the number of atoms required.

I hope this helps! Let me know if you have any further questions.