Oct 14, 2019 Thread starter #1 A Another Member Feb 11, 2018 30 \(\displaystyle (a+b)^{a+b}=a^a+y\) ; sorry i am edited a^b to a^a Suppose we know a and b. y in the term of a, b? Last edited: Oct 14, 2019

\(\displaystyle (a+b)^{a+b}=a^a+y\) ; sorry i am edited a^b to a^a Suppose we know a and b. y in the term of a, b?

Oct 14, 2019 Admin #2 Ackbach Indicium Physicus Staff member Jan 26, 2012 4,184 How about $$y=(a+b)^{a+b}-a^b? $$