How to solve general forces equations as variables?

In summary: This comes from Fnet = μsFn-Fcosθ please define your variables.3) Find the acceleration of the object when F is doubled.For this I know that Fnet = ma, so a = Fnet/m Where do i go from there? I get how forces work, and drew diagrams, but I need help in understanding how the equations themselves will be used, only as variables (which our teacher gives on tests), i know how to use the math, and can do it with calc, but i want to learn how to manipulate the equations and use Fnet = ma to solve them.
  • #1
PhoniexGuy
26
0
Okay, so we were doing forces, and my teacher had this question:

Code:
In an atwood machine, a massless, non stretching string passes over a frictionless peg, 
one end of the rope is connected to object m1, and the other end to object m2 (heavier).
When the system is released from rest, m2 goes down and m1 goes up, find acceleration.
So she started out with

Fnet = ma
Then here is where I got confused: She goes to:
Fnet = FT - Fg.

For the second equation, how do you just pull this out, and why does it work, i mean i get the math and can do it, but i don't know why?
 
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  • #2
Draw a free body diagram for both mass m1 and mass m2 then sum up the forces acting on each.
 
  • #3
Welcome to PF!

Hi PhoniexGuy! Welcome to PF! :smile:
PhoniexGuy said:
Then here is where I got confused: She goes to:
Fnet = FT - Fg.

For the second equation, how do you just pull this out, and why does it work, i mean i get the math and can do it, but i don't know why?

For one object, there are two forces acting on it:

its own weight (mg), and the tension in the rope (FT) :wink:
 
  • #4


tiny-tim said:
Hi PhoniexGuy! Welcome to PF! :smile:For one object, there are two forces acting on it:

its own weight (mg), and the tension in the rope (FT) :wink:

Oh, okay, then thank you, i get it now. Is it negative Fg since gravity is downwards?
 
  • #5
PhoniexGuy said:
Oh, okay, then thank you, i get it now. Is it negative Fg since gravity is downwards?

not exactly

Fg and FT have opposite signs because they act in opposite directions :wink:

(since signs obviously worry you, i'll anticipate the next question …

in your two F = ma equations for the two different objects, depending how you set them up, it needn't be the same a in both equations … one may have a and the other may have minus a)
 
  • #6
Okay, because that's what our teacher did, is this because the objects are attached by the rope?

Also, still related to forces:

I have a 10 Kg block that is pushed with force F at a angle θ (in degrees) to the horizontal. I have a few questions about the equations for certain things and there is μs and μk:

1) I know that to find normal force
Code:
F[SUB]n[/SUB] = F[SUB]w[/SUB] - F(sin θ)
2) I also know then to find frictional force?
Code:
F[SUB]f[/SUB] = μ[SUB]s[/SUB]F[SUB]n[/SUB]-[b]F[/b]cosθ

I understand how to use them, but how do you get these equations? Like how can you derive them from something else?

3) Find the acceleration of the object when F is doubled.

For this I know that Fnet = ma, so a = Fnet/m Where do i go from there? I get how forces work, and drew diagrams, but I need help in understanding how the equations themselves will be used, only as variables (which our teacher gives on tests), i know how to use the math, and can do it with calc, but i want to learn how to manipulate the equations and use Fnet = ma to solve them.
 
  • #7
PhoniexGuy said:
I have a 10 Kg block that is pushed with force F at a angle θ (in degrees) to the horizontal.
Pushed on a horizontal plane with a force that's angled? Up or down?
Or pushed up or down a slope that's at θ to horizontal?
1) I know that to find normal force
Code:
F[SUB]n[/SUB] = F[SUB]w[/SUB] - F(sin θ)
Please define your variables.
 
  • #8
Hi PhoniexGuy! :smile:

(just got up :zzz:)
PhoniexGuy said:
Okay, because that's what our teacher did, is this because the objects are attached by the rope?

yes, the length of the rope is constant, so the displacement of the two ends must have the same magnitudes …

and of course, by differentiating, that means that the velocities of the two ends, and the accelerations of the two ends, must also have the same magnitudes

(this equation, a1 = -a2, is known as a constraint

it's a geometry equation, not a physics one! :wink:)
I have a 10 Kg block that is pushed with force F at a angle θ (in degrees) to the horizontal. I have a few questions about the equations for certain things and there is μs and μk:

1) I know that to find normal force
Code:
F[SUB]n[/SUB] = F[SUB]w[/SUB] - F(sin θ)
2) I also know then to find frictional force?
Code:
F[SUB]f[/SUB] = μ[SUB]s[/SUB]F[SUB]n[/SUB]-[b]F[/b]cosθ

I understand how to use them, but how do you get these equations? Like how can you derive them from something else?

you mean, the teacher has given you the formulas, but you want to be able to derive them yourself?

1) this comes from good ol' Newton's second law (F = d(mv)/dt)

(as indeed does nearly all of mechanics!)

… you know that the acceleration in the normal direction is 0 (obviously! :biggrin:)

so, applying Newton, no matter what is going on on the surface, Fnet in the normal direction must be zero

there are only three forces with normal components, Fn, Fw, and F, and if you apply the relevant cosines, equation 1) is what you get! :smile:

2) this equation seems to be written wrong :confused:

it looks like the equation Fnet, horizontal = Fcosθ - µsN
3) Find the acceleration of the object when F is doubled.

For this I know that Fnet = ma, so a = Fnet/m Where do i go from there? I get how forces work, and drew diagrams, but I need help in understanding how the equations themselves will be used, only as variables (which our teacher gives on tests), i know how to use the math, and can do it with calc, but i want to learn how to manipulate the equations and use Fnet = ma to solve them.

i'm not sure exactly what the question is

anyway, can you show us how far you've got on it?
 
  • #9
Actually, nevermind. Thank's for all the help, i understand it now! (asked teacher)
 

Related to How to solve general forces equations as variables?

1. What are general forces equations?

General forces equations are mathematical expressions that describe the relationship between various forces acting on an object. They take into account factors such as magnitude, direction, and position of the forces.

2. Why is it important to solve general forces equations as variables?

Solving general forces equations as variables allows for the determination of unknown variables such as force, acceleration, or position. This is crucial in understanding and predicting the motion of objects.

3. What are the steps to solve general forces equations as variables?

The steps to solve general forces equations as variables are: 1) Identify all the forces acting on the object, 2) Draw a free-body diagram, 3) Write down the general forces equations for the object, 4) Substitute known values and variables into the equations, 5) Solve for the unknown variables.

4. What are some common types of forces included in general forces equations?

Some common types of forces included in general forces equations are gravitational force, normal force, frictional force, tension force, and applied force. Other forces such as air resistance or magnetic force may also be included depending on the specific scenario.

5. Can general forces equations be used to solve real-world problems?

Yes, general forces equations can be used to solve real-world problems as they provide a mathematical framework for analyzing and understanding the forces acting on objects. They can be applied in a variety of fields such as engineering, physics, and mechanics.

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