How to prove M = 2.016 X D (M = 2D)

  • Thread starter Indranil
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In summary, to get molecular weight of Hydrogen from this formula 2D = M, if atomic weight of hydrogen is 1.008, you need to find D.
  • #1
Indranil
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Homework Statement


How to prove M = 2.016 X D (M = 2D) if the atomic weight of Hydrogen is 1.008

Homework Equations



How to prove M = 2.016 X D (M = 2D).if the atomic weight of Hydrogen is 1.008

The Attempt at a Solution


As I know,
D = the mass of one molecule of gas / the mass of one molecule of H2
= the mass of one molecule of gas / the mass of 2 molecules of H atoms
= 1/2 X the mass of one molecule of gas / the mass of one H atom
= 1/2 X the molecular mass of gas
= 1/2 X M
If I put the value in the equation above I get
D = one molecule of gas / 2 molecules of H atoms
= 2.016 / 1.008 X 1.008
= 2.016 / 2.016
= 1
 
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  • #2
Indranil said:

Homework Statement


How to prove M = 2.016 X D (M = 2D) if the atomic weight of Hydrogen is 1.008
Is that the actual statement of the problem? What are M and D? And you have two equations there, which is the correct one?
 
  • #3
DrClaude said:
Is that the actual statement of the problem? What are M and D? And you have two equations there, which is the correct one?
Yes
'M' means 'molecular mass' and 'D' means 'vapour density'
The two equations are correct
D = the mass of one molecule of gas / the mass of one molecule of H2
= the mass of one molecule of gas / the mass of 2 molecules of H atoms
= 1/2 X the mass of one molecule of gas / the mass of one H atom
= 1/2 X the molecular mass of gas
= 1/2 X M
2D = M
if the atomic weight of Hydrogen is 1.008, then how to get M = 2.016 X D, I tried below but did not get
If I put the value in the equation above I get
D = one molecule of gas / 2 molecules of H atoms
= 2.016 / 1.008 X 1.008
= 2.016 / 2.016
= 1
 
  • #4
The problem is that M is not the mass of one molecule of gas/ the mass of one H atom. It is the mass of one molecule of gas/(1/12)*the mass of one 12C atom. On the carbon-12 scale, the atomic weight of hydrogen is 1.008.
 
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  • #5
Indranil said:
'D' means 'vapour density'

D = the mass of one molecule of gas / the mass of one molecule of H2

Ratio of masses is not the vapor density, vapor density is mass/volume. Something is very wrong here.
 
  • #6
Borek said:
Ratio of masses is not the vapor density, vapor density is mass/volume. Something is very wrong here.
only density = mass / volume but vapour density or relative density D = M / 2
 
  • #7
Relative density is unitles, vapor density has units of mass/volume. These are two completely different properties.

It is still not clear what the question really is.
 
  • #8
Borek said:
Relative density is unitles, vapor density has units of mass/volume. These are two completely different properties.

It is still not clear what the question really is.
How to get molecular weight of Hydrogen from this formula 2D = M, If atomic weight of hydrogen is 1.008? (where 'D' is vapor density, and 'M' is molecular weight)
 

Related to How to prove M = 2.016 X D (M = 2D)

1. How do you prove the equation M = 2.016 X D?

To prove this equation, we can use mathematical manipulation and substitution. We can start by dividing both sides by 2, which gives us M/2 = 2.016 X D/2. Then, we can substitute D/2 with x, which gives us M/2 = 2.016 X x. Finally, we can solve for x by dividing both sides by 2.016, which gives us x = M/(2 X 2.016). Therefore, we have proven that M = 2.016 X D.

2. What does the constant 2.016 represent in the equation M = 2.016 X D?

The constant 2.016 represents the conversion factor between the unit of measurement for M and D. In other words, it is the number that you multiply D by in order to get the value of M. This constant can vary depending on the units used for M and D. For example, if M is measured in meters and D is measured in kilometers, the constant would be different.

3. Can this equation be used for any type of measurement?

Yes, this equation can be used for any type of measurement as long as the units for M and D are compatible. However, the constant 2.016 may need to be adjusted depending on the units used.

4. How do you determine the accuracy of this equation?

The accuracy of this equation can be determined by comparing the calculated values of M and D using this equation with the actual measured values. If the calculated values closely match the actual values, then the equation can be considered accurate. Additionally, the accuracy can also be improved by increasing the number of significant figures used in the calculation.

5. Is this equation a universal law in science?

No, this equation is not a universal law in science. It is a mathematical expression that is used to represent a relationship between two variables, but it is not a fundamental law or principle in science. It may be applicable in certain contexts or for certain measurements, but it is not a universally accepted law.

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