How to interpret the given informations in physics problems

In summary: A skier is being pulled along a horizontal surface at constant speed with a force of 50.0 N. What is the weight of the skier?In summary, a skier is being pulled with a force of 50.0 N along a horizontal surface at constant speed. To determine the weight of the skier, it is important to recognize that constant speed implies a balance of forces. Therefore, the weight of the skier can be calculated by using the equation weight = coefficient of kinetic friction x force applied, which in this case is 0.05 x 50.0 N, resulting in a weight of 1000 N. It is important to note that in this scenario, the force of 50.0
  • #1
gracy
2,486
83

Homework Statement

:A skier is being pulled along a horizontal surface at constant speed with a force of 50.0 N. What is the weight of the skier?coefficient of kinetic friction=0.05.
My main problem is that what "at constant speed" implies here?i.e A skier is being pulled along a horizontal surface going at constant speed or
A skier ,when pulled along a horizontal surface attains constant speed.

When I was given this to solve, I thought that
A skier is being pulled along a horizontal surface going at constant speed
,but when viewed the solution the other was true.

I know how to solve this in this case .I am filling the template .But my real problem is what is wrong in my interpretation.How to avoid such wrong interpretations.
[/B]

Homework Equations

:at constant speed
force applied=fk[/B]

The Attempt at a Solution

:50N=0.05 multiplied by weight
weight=1000 N.[/B]
 
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  • #2
gracy said:
My main problem is that what "at constant speed" implies here?i.e A skier is being pulled along a horizontal surface going at constant speed or
A skier ,when pulled along a horizontal surface attains constant speed.

When I was given this to solve, I thought that
A skier is being pulled along a horizontal surface going at constant speed
,but when viewed the solution the other was true.

I believe you were correct (A skier is being pulled along a horizontal surface going at constant speed).

Why do you think the two options are different? The skier ends up at a constant speed in both cases.
 
  • #3
CWatters said:
Why do you think the two options are different?
Because if I interpret this as A skier is being pulled along a horizontal surface going at constant speed
I will not come to the below conclusion.
force applied=fk
will I?
 
  • #4
Why not? Constant speed implies no acceleration. Zero acceleration means the net horizontal force acting on the skier is zero. Therefore the two forces friction and tension must be equal (and opposite).
 
  • #5
CWatters said:
Why not?
By skier is being pulled along a horizontal surface going at constant speed I mean
skier was going at constant speed and then horizontal force acted on it ,What happens after that is not known whether or not it balances friction.
CWatters said:
Constant speed implies no acceleration. Zero acceleration means the net horizontal force acting on the skier is zero. Therefore the two forces friction and tension must be equal (and opposite).
You are also answering in
,when pulled along a horizontal surface attains constant speed this context.
 
  • #6
I would interpret it as the force pulling the skier cause him to travel at a constant speed (because there is a frictional force opposing his motion). So the force is the cause and the effect of it is constant speed, which is the second case you mentioned.
 
  • #7
By skier is being pulled along a horizontal surface going at constant speed I mean
skier was going at constant speed and then horizontal force acted on it...

Ah ok, that interpretation hadn't occurred to me. The original problem says..

A skier is being pulled along a horizontal surface at constant speed with a force of 50.0 N

I think it's pretty clear the 50N force is doing the pulling and it isn't a force that's applied later.

I suppose it might have been clearer had it said

A skier is being pulled along a horizontal surface at constant speed BY a force of 50.0 N

Anyway the key to interpreting the problem is to recognise that "constant speed" implies a balance of forces.
 
  • #8
Ok,how would you interpret this one
A 53. kg block, slowed by friction, has an acceleration of -0.1 m/s2. What is the force of friction on the block?

Block has acceleration of -0.1 m/s2 after slowing down?Right?
 
  • #9
gracy said:
Ok,how would you interpret this one
A 53. kg block, slowed by friction, has an acceleration of -0.1 m/s2. What is the force of friction on the block?

Block has acceleration of -0.1 m/s2 after slowing down?Right?
The block has an acceleration of -0.1 m/s2 while it is slowing down.
 
  • #10
jbriggs444 said:
while it is slowing down
in the process of slowing down?
 
  • #11
gracy said:
in the process of slowing down?
Yes.

After the block has finished slowing and has come to a stop, its acceleration will not be -0.1 m/s2. It will be zero. So it makes no sense to understand the problem as specifying the acceleration after slowing down. In addition, if we know the acceleration now, it does not matter what the acceleration was previously. So again, it makes little sense to understand the problem as specifying the acceleration after slowing down.

One of the first rules of problem interpretation is that if an interpretation does not make sense, it is not the interpretation that was intended.

[The tricky part is handling situations where none of the possible interpretations make sense]
 
  • #12
gracy said:
Block has acceleration of -0.1 m/s2 after slowing down?Right?
jbriggs444 said:
So it makes no sense to understand the problem as specifying the acceleration after slowing down
I meant after slowing down to some extent it will have acceleration of -0.1 m/s2 .
 
  • #13
jbriggs444 said:
After the block has finished slowing and has come to a stop, its acceleration will not be -0.1 m/s2. It will be zero.
If some object has stopped slowing down,does it necessarily imply that it is at rest or moving with constant speed?cannot it be speeding up?
 
  • #14
A "53 kg block slowed by friction" will not end up moving with a constant non-zero speed and will not speed up. It will come to rest and stay at rest... Barring some unexpected problem setup.

Yes, if the block were sliding across sandpaper and came to a patch of ice, it could indeed stop slowing and proceed at a constant speed. And if the block were sliding across sandpaper to the rear on a train that is moving forward then it could indeed stop slowing and begin speeding up (as measured against the ground).

Rule 2 of problem interpretation: If the problem does not mention icy patches or trains, assume that there are no icy patches or trains.
 
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Likes gracy
  • #15
Block has constant acceleration of -0.1 m/s2 throughout the slowing process,right?
 
  • #16
The only acceleration that we can care about is the acceleration that is given. This pretty much comes under the heading of ice patches and trains. If the acceleration is given as -0.1 m/s2 then you should not concern yourself with the possibility that the acceleration is different from -0.1m/s2.

Edit: You should look at the problem statement again. It does not ask you for the force throughout some process. It just asks you for the force. Even if the acceleration varies throughout the process of slowing down, the only thing that matters to determine the force at a particular moment is the acceleration at that moment. Any concern about whether the acceleration is constant is irrelevant.
 
Last edited:
  • #17
gracy said:
A 53. kg block, slowed by friction, has an acceleration of -0.1 m/s2. What is the force of friction on the block?

+1 to what jbriggs444 said.

You can't solve the problem unless you assume that it's the friction causing the deceleration. It's a simple f=ma problem.
 

Related to How to interpret the given informations in physics problems

1. How do I know which equations to use to interpret the given information?

To determine which equations to use, first identify the known values and the unknown value in the problem. Then, look for equations that involve those variables. Also, pay attention to any given units, as they can help guide you towards the correct equation.

2. What do I do if there are multiple equations that seem applicable to the given information?

In this case, you can use algebraic manipulation to rearrange the equations and solve for the unknown value. You can also use substitution, where you plug in the known values into each equation and see which one gives the most accurate answer.

3. Is it important to consider the units of the given information when interpreting it?

Yes, it is crucial to pay attention to the units given in the problem. Units can help you determine which equations to use and also ensure that your final answer is in the correct units.

4. How can I check if my interpretation of the given information is correct?

You can check your interpretation by plugging in your calculated values into the original equations given in the problem. This will help you see if your answer makes sense and is consistent with the given information.

5. Are there any common mistakes to avoid when interpreting information in physics problems?

Some common mistakes to avoid include not paying attention to the units, not understanding the given information, and not using the correct equations. It is also essential to double-check your calculations and make sure you are using the correct values and units throughout the problem.

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