Combine the two series resistors first (what is the equation for combining series resistors?), and then combine the two resulting parallel resistors.nfcfox said:
Isn't there only one series resistor? I'm still not sure how to do this...berkeman said:Combine the two series resistors first (what is the equation for combining series resistors?), and then combine the two resulting parallel resistors.
Ok ok I see now. So the resistor on top is added with the one on the right or left then that is put in parallel with the other one... Still kind of weird though because after adding those 2 resistors, wouldn't it not be in parallel after that?NascentOxygen said:
Right or left? Which one is in series with the resistor on top?nfcfox said:
I think the right.cnh1995 said:
Yes. So what do you get for the answer? Please show your work.nfcfox said:
I already have the answer I found it... I'm just confused as to why adding the 2 10 resistors would then put that in parallel with the last one.berkeman said:Yes. So what do you get for the answer? Please show your work.
No this is just something I made on a gizmo. It's part of a problem I am doing.epenguin said:Was this question meant to test knowledge of resistor colour coding (which I am long unfamiliar with - does it still exist?), the actual calculation being assumed trivial?
Adding the two 10 ohm resistors will give series equivalent resistance Req of them. How are Req and the remaining 10 ohm resistor connected?nfcfox said:
I've added unique identifying labels to the resistors in the figure in post #8. Can you tell us which two resistors you added together and which is the "last one" that you combined with the sum?nfcfox said:
R3 and R2 as series then that with R1 as parallel.gneill said:
I believe that you've misunderstood the problem. It is an entry level problem with three resistors, all 10 Ω. The goal is to reduce the given network to a single equivalent resistance value. It requires the concepts of recognizing series and parallel pairs of resistances and combining said pairs into single values. Eventually a single value representing the entire network's equivalent resistance is achieved.justaman0000 said:
Correct.nfcfox said:
To calculate the equivalent resistance of a series circuit, simply add up the individual resistances of each component. This is because in a series circuit, the current is the same throughout, so the total resistance is equal to the sum of the individual resistances.
The formula for calculating equivalent resistance in a parallel circuit is 1/Req = 1/R1 + 1/R2 + 1/R3 + ..., where R1, R2, R3, etc. are the individual resistances of each component. This is because in a parallel circuit, the voltage is the same across each component, so the total resistance is equal to the reciprocal of the sum of the reciprocals of the individual resistances.
To find the equivalent resistance of a complex circuit, you can use a combination of series and parallel circuit rules. Start by simplifying any series or parallel sections of the circuit, and then use the simplified values to calculate the equivalent resistance of the entire circuit. Alternatively, you can use the Kirchhoff's laws to solve for the equivalent resistance.
No, Ohm's law only applies to simple circuits with one resistor. To find the equivalent resistance of a complex circuit, you need to use a combination of circuit rules and equations.
Finding the equivalent resistance of a circuit is important because it allows us to simplify complex circuits into a single equivalent resistor, making it easier to analyze and understand the behavior of the circuit. It also helps in determining the total power and current in the circuit.