How to deal with INVERSE TANGENT?

[bmed90]

Homework Statement

Find X. Given the following Equation2.094 radians =tan^-1(2*x*(1.11)/1-(1.11)^2)

Homework Equations

The Attempt at a Solution

How do you get rid of inverse tangent?

Here's what i got

tan(2.094((180/pi))*(1-(1.11)^2) / 2*1.11 = X

 

[Mark44]

Homework Statement

Find X. Given the following Equation


2.094 radians =tan^-1(2*x*(1.11)/1-(1.11)^2)

This -- (2*x*(1.11)/1-(1.11)^2) -- is missing some parentheses.

Is it supposed to be this?
$$ \frac{2x \cdot 1.11}{(1 - 1.11)^2}$$

Homework Equations

The Attempt at a Solution

How do you get rid of inverse tangent?

Take the tangent of both sides.

Here's what i got

tan(2.094((180/pi))*(1-(1.11)^2) / 2*1.11 = X

 

[bmed90]

No, the 1.11 in the denominator is squared instead of (1-1.11)^2

So the denom is

(1-(1.11)^2)Sorry my mistake

 

[brmath]

You are doing the right thing, taking the tangent of both sides. However you do not want to use the ##180/\pi## which converts radians to degrees. (Also, if you really wish to convert back to degrees, you have to convert everything, not just one factor. )

Usually if there is an x involved we assume we are in radians, which are really arclength, and so compatible with lengths on the x-axis.

Go ahead and compute it out.