How to Calculate Partial Pressure of NOCl in a Chemical Reaction?

[aaronfue]

Homework Statement

I am given the following equation:

2NO (g) + Cl₂ (g) [itex]\rightleftharpoons[/itex] 2NOCl (g)

K_p = 6.5×10⁴
P_NO = 0.35 atm
P_Cl2 = 0.10 atm

I need to calculate P_NOCl.

Homework Equations

K_p = [itex]\frac{(P_{NOCl})^2}{(P_{NO})^2*(P_{Cl_2})}[/itex]

The Attempt at a Solution

I was given K_p = 6.5×10⁴

After plugging in my partial pressures for NO and Cl₂ I got:

P_NOCl = [itex]\sqrt{(6.5×10^4)*(0.35)^2*(0.10)}[/itex]

Is this the correct way to calculate this?

Thanks!

 

[Bill Nye Tho]

That looks good to me!