How to calculate Microwave Power

[CL39]

-If you have a magnetron produce __# of microwaves, each with frequency
of __ MHz, how can one calculate the power of those microwaves (in watts)?


-the microwaves have electric field and magnetic field associated with
them, taking just one microwave (in the waveguide) and its associated electric field,
if you had another microwave in phase, does the electric field
simply double?


Thank you.

 

[Born2bwire]

You need to know the amplitudes of the waves to calculate the power. You could easily measure the power delivered though. Have a large, large mouthed glass container with water at room temperature. Heat it for a specific amount of time in the microwave, measure the temperature difference, calculate the amount of energy absorbed and use the time to find the average power absorbed. You could get a ballpark estimate by looking up the specs of the magnetron or the microwave itself.

 

[astrokreng]

To calculate the power of microwaves, we can use the formula P = E^2/2Z, where P is power, E is electric field, and Z is the impedance of the medium through which the microwaves are traveling. In this case, the medium would be the waveguide.

To determine the electric field of a single microwave, we can use the formula E = V/d, where V is the voltage and d is the distance between the two plates of the waveguide. We can then use this value of E in the power formula to calculate the power of the single microwave.

If we have two microwaves in phase, the electric fields will add together, resulting in a doubling of the total electric field. However, this does not necessarily mean that the power will double as well. This is because power is proportional to the square of the electric field, so doubling the electric field will result in a quadrupling of the power.

Therefore, to calculate the power of two microwaves in phase, we would need to take the power of one microwave and multiply it by four. This same principle can be applied to any number of microwaves in phase. However, it is important to note that in reality, there may be losses and inefficiencies in the system that could affect the actual power output.