It only seems easy because you were able to astutely note that the work-energy theorem would give you the answer for total work done. Others might have tried to find force/distance/acceleration etc., to use in calculating the work done, but to no avail.mmiller9913 said:Homework Statement
Determine the amount of work done in firing a 2.0-kg projectile with an initial speed of 50 m/s. Neglect any effects due to air resistance
Homework Equations
W = delta K
K = 1/2mv^2
The Attempt at a Solution
just take K= 1/2(2)(50)^2 to get 2500 J...it seems to easy?
The work done when firing a projectile is the amount of energy that is transferred to the projectile by the force used to launch it. This work is typically measured in joules (J).
The work done when firing a projectile can be calculated using the formula W = Fd, where W is work, F is the force applied, and d is the distance over which the force is applied. This formula assumes that the force is constant and in the same direction as the displacement.
The amount of work done when firing a projectile is affected by several factors, including the mass and velocity of the projectile, the angle at which it is fired, and the resistance of the medium it is traveling through (such as air resistance).
The work done when firing a projectile is directly related to the kinetic energy of the projectile, which in turn affects its velocity and trajectory. The greater the work done, the greater the kinetic energy and therefore the faster the projectile will travel.
Work done and power are related concepts but have different units of measurement. Work done is a measure of the total energy transferred to the projectile, while power is a measure of how quickly the work is done. Power is calculated by dividing the work done by the time it takes to do the work.