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How many white balls in the container must be at least so that the probability that two black balls were drawn was < 23/30

ghostfirefox

New member
Nov 13, 2019
14
We have 27 balls in the container, some of which are white and some black. How many white balls in the container must be at least, so that the probability that two black balls were drawn at random without a return was less than 23/30?
 
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HallsofIvy

Well-known member
MHB Math Helper
Jan 29, 2012
1,151
We have 27 balls in the container, some of which are white and some black. How many white balls in the container must be at least, so that the probability that two balls were drawn at random without a draw was less than 23/30?
What?? "Two balls are drawn at random without a draw"?? What does that mean? Did you mean "two white balls are drawn without a black ball being drawn"? Is this drawing without replacement? If so let "n" be the number of white balls in the container. The probability the first ball drawn is white is n/27. If that happens there are 26 balls left in the container, n-1 of them white. The probability the second ball drawn is also white is (n-1)/26. The probability both balls are white is [n(n-1)]/702. You want to solve the inequality (n^2- n)/702< 23/30.
 

ghostfirefox

New member
Nov 13, 2019
14
You're right a I missed a word. I corrected the exercise. Thank for your response.
 
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