You can, but it's just extra work here.C. Lee said:You can calculate the maximum height of the ball using given initial speed.
haruspex said:You can, but it's just extra work here.
Lana, what equations do you know which may be relevant? Does SUVAT mean anything to you?
The time it takes for an object to reach the ground from a certain height depends on several factors such as the initial height, the gravitational force, and air resistance. In a vacuum, all objects fall at the same rate regardless of their mass, and it takes approximately 4.9 seconds to reach the ground from a height of 100 meters.
The shape and size of an object do not affect the time it takes to reach the ground, as long as air resistance is negligible. In a vacuum, both a feather and a bowling ball would fall at the same rate and take the same amount of time to reach the ground.
Air resistance, also known as drag, can significantly affect the time it takes for an object to reach the ground. The larger the surface area of the object, the more air resistance it experiences, and the longer it takes to fall. This is why a feather takes longer to reach the ground than a bowling ball in the presence of air resistance.
No, the time it takes to reach the ground on other planets may vary depending on the planet's mass and gravitational force. For example, on Mars, which has a weaker gravitational force than Earth, it would take longer for an object to reach the ground from the same height.
Yes, the time it takes to reach the ground can be calculated using the equation t = √(2h/g), where t is the time, h is the initial height, and g is the gravitational acceleration. However, this equation assumes a vacuum and negligible air resistance. In real-world scenarios, the time may vary due to the presence of air resistance.