How is the equation given for v_b tangent to it?

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In summary, the conversation discusses a confusion about the tangent velocity vector v_b in a solved example. The asker is unsure about the equation given for v_b and whether it is tangent to the path. The responder explains that the right triangle on the radius of the circular path indicates that v_b has equal horizontal and vertical components, clarifying the understanding.
  • #1
kostantina
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Homework Statement



I'm trying to follow a solved example in the book. I understand everything except one "trivial" (for most of you) analysis of the tangent velocity vector v_b. Because v_b is unknown it is written as its magnitude times the direction it follows constrained in a circular path.

However, my understanding of v_b written as in the picture followed is not tangent. That is the vector that describes the radius of the path, and not the perpendicular to the radius which will be the instantaneous velocity.


Homework Equations


Please see attached picture


The Attempt at a Solution


how is the equation given for v_b tangent to it? this is the vector describing the radius of the path?

Thank you
 

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  • #2
That right triangle with sides 1 and 1, on the radius of the circular path, indicates that at the current position B is constrained to moving as much to the right as upwards, per unit of time, meaning a velocity vector having equal horiz and vertical components, at the instant represented.
 
  • #3
Thank you, makes sense now. Wish I'd asked earlier.
 

Related to How is the equation given for v_b tangent to it?

1. How is the equation for vb tangent to it given?

The equation for vb tangent to a curve is given by taking the derivative of the curve's equation and evaluating it at the point where the tangent line intersects the curve. This derivative is equal to the slope of the tangent line, which can be used to find the equation of the line using the point-slope form.

2. What is the significance of the equation for vb tangent to it?

The equation for vb tangent to a curve is significant because it represents the instantaneous rate of change of the curve at a specific point. This can be useful in understanding the behavior of the curve and predicting its future values.

3. How do you determine the point where the tangent line intersects the curve?

The point of intersection between the tangent line and the curve can be found by setting the derivative of the curve equal to the slope of the tangent line and solving for the variable. This will give you the x-coordinate of the point of intersection. To find the y-coordinate, plug the x-value into the original equation of the curve.

4. Can the equation for vb tangent to it be used for any type of curve?

Yes, the equation for vb tangent to a curve can be used for any type of curve, including linear, quadratic, exponential, and trigonometric functions. The only requirement is that the curve must be differentiable at the point where the tangent line is being evaluated.

5. How is the equation for vb tangent to it related to the concept of limits?

The equation for vb tangent to a curve is closely related to the concept of limits because it involves finding the instantaneous rate of change, which can be thought of as the limit of the average rate of change as the interval approaches zero. Additionally, the point of tangency is the point where the slope of the tangent line is equal to the limit of the slope of the secant line as the interval approaches zero.

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