How Is Heat Transferred in Different Paths of a P-V Diagram Cycle?

In summary, the net work done in the cycle abca is +1.2 J. Along path ab, the gas does work on the surroundings, resulting in a positive work done of 5.3 J. Along path ca, the gas gains energy as heat, with a positive value of +2.8 J. To find the amount of energy transferred as heat along path ab, we can use the equation DU = W + Q and plug in the given values for DU and W. This results in Q = 2.9 - 5.3 = -2.4 J. However, this is not the correct answer as work is positive when the gas expands. Therefore, the correct answer is Q = 2.9
  • #1
Azndoode1
11
0

Homework Statement




A sample of gas is taken through the cycle abca shown in the p-V diagram of Fig. 19-9. The net work done is +1.2 J. Along path ab, the change in the internal energy is +2.9 J and the magnitude of the work done is 5.3 J. Along path ca, the energy transferred to the gas as heat is +2.8 J.
W0412-N.jpg

(a) How much energy is transferred to the gas as heat along path ab?
(b) How much energy is transferred to the gas as heat along path bc?

Homework Equations



DU = W + Q


The Attempt at a Solution



I figured it might be 2.9 - 5.3 = -2.4 for part A.
But, its not the right answer...
 
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  • #2
Along path ab, work is positive because the gas is expanding. When you got expansion, work is positive. Therfore, it can't be -5,3 it's +5,3.

Along path bc, work is negative (compression). Along path ac, there is no work done, because there is no change in the volume.
 
  • #3
Azndoode1 said:

Homework Equations



DU = W + Q
You need to be clear on what the quantities Q and W stand for. Q is the amount of heat flowing into the gas. If heat flows out of the gas, Q would be negative. Similarly, W is the amount of work done on the gas by the surroundings. If the gas does work on the surroundings, W would be negative.

So for part (a), the gas expanded. So does it do 5.3 J of work on the surroundings or did the surroundings do 5.3 J of work on the gas?
 
  • #4
The correct answer was actually +8.2...
 
  • #5
method_man said:
Along path ab, work is positive because the gas is expanding. When you got expansion, work is positive. Therfore, it can't be -5,3 it's +5,3.

Along path bc, work is negative (compression). Along path ac, there is no work done, because there is no change in the volume.

vela said:
You need to be clear on what the quantities Q and W stand for. Q is the amount of heat flowing into the gas. If heat flows out of the gas, Q would be negative. Similarly, W is the amount of work done on the gas by the surroundings. If the gas does work on the surroundings, W would be negative.

You are being told two different things here. But it doesn't necessarily matter how you define your system as long as you can stay consistent.

As far as the answer 8.2 goes, that seems correct to me.
You have an isobaric expansion, and anytime something expands it does work on the surroundings. So for simplicity sake let's say that the gas had to sacrifice how compressed it was to do work on the surroundings. So your gas has just lost 5.3J.
But then it goes to tell you that the gas actually gained 2.9J overall. The only place it can gain energy is from heat. So how many Joules of heat did it gain to bring the overall internal energy increase to 2.9J?

Let me know if that makes sense.
 
  • #6
Azndoode1 said:
The correct answer was actually +8.2...
So what's your point? It doesn't really help to get the correct answer if all you did was randomly add and subtract numbers until you found it. You need to understand what the variables and equations mean so you can get the correct answer without just guessing.
 

Related to How Is Heat Transferred in Different Paths of a P-V Diagram Cycle?

1. What is a P-V diagram in thermodynamics?

A P-V (pressure-volume) diagram is a graphical representation of the relationship between the pressure and volume of a system undergoing a thermodynamic process. It is commonly used in thermodynamics to visualize and analyze the changes in pressure and volume of a gas or liquid as it undergoes a change in state.

2. How is a P-V diagram constructed?

A P-V diagram is constructed by plotting the pressure on the y-axis and the volume on the x-axis. The curve on the diagram represents the path of the system as it undergoes a change in state. The area under the curve represents the work done by the system.

3. What information can be obtained from a P-V diagram?

A P-V diagram can provide information about the efficiency of a thermodynamic process, the work done by the system, and the changes in pressure and volume of the system. It can also be used to determine the heat transfer during a process.

4. How does the shape of a P-V diagram indicate the type of process?

The shape of the curve on a P-V diagram can indicate whether the process is isobaric (constant pressure), isochoric (constant volume), isothermal (constant temperature), or adiabatic (no heat transfer). For example, an isobaric process will have a horizontal line on the diagram, while an isochoric process will have a vertical line.

5. Can a P-V diagram be used for both gases and liquids?

Yes, a P-V diagram can be used for both gases and liquids. However, for a liquid, the curve on the diagram will be almost vertical as liquids are incompressible and have a constant volume. On the other hand, gases can undergo significant changes in volume and pressure, resulting in a more curved line on the diagram.

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