- #1
Woolyabyss
- 143
- 1
A passenger train, which is traveling at 80 m/s is 1500 m behind a goods train which is traveling at 30 m/s in the same direction on the same track. At what rate must the passenger train decelerate to avoid a crash?
My attempt at the question:
V=u+at 0=80+at a=-80/t
I tried to find at what time their distances were equal using
s=ut+1/2 (a)(t^2)
80t +1/2 (-80/t) t^2-1500=30t
Simplify and I got 10t=1500
t=150
sub value of t into original equation and you get a=-8/15 m/s^2
The back of my book says its 5/6 m/s^2
Any help would be appreciated
My attempt at the question:
V=u+at 0=80+at a=-80/t
I tried to find at what time their distances were equal using
s=ut+1/2 (a)(t^2)
80t +1/2 (-80/t) t^2-1500=30t
Simplify and I got 10t=1500
t=150
sub value of t into original equation and you get a=-8/15 m/s^2
The back of my book says its 5/6 m/s^2
Any help would be appreciated