- #1
Krappy
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Homework Statement
A block of wood, of side 2a and mass M is on an horizontal plane. When it turns, it does it over the edge AB. A bullet of mass m<<M and velocity v hits on the opposite face to ABCD, at a height of 4/3*a. The bullets gets stuck on the block. Find the minimum value of v so that the cube turns over AB and falls on the face ABCD.
Homework Equations
[tex]\frac{d\vec{L}}{dt} = \vec{\tau}[/tex]
[tex]\vec{L} = I\vec{\omega} = \vec{r} \times \vec{p}[/tex]
[tex]\vec{\tau} = \vec{r} \times \vec{F} = I\vec{\alpha}[/tex]
[tex]\Delta p = 0[/tex]
The Attempt at a Solution
I've tried conservation of energy [tex]1/2(M+m)(\frac{m}{2(M+m)}v)^2 = (m+M)a(\sqrt(2)-1)g[/tex] but this doesn't depend on the height at which the bullet hits the block.
I've also thought of integrating [tex]\frac{d\vec{L}}{dt} = \vec{\tau}[/tex]
but the Torque is not constant and depends on the angle between the diagonal of the cube and the gravity.
I've ran out of ideas.
[PLAIN]http://img855.imageshack.us/img855/3033/picture1ic.png
Regards
Johnny
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