How Does Friction Affect a Puck Sliding Up an Inclined Plane?

In summary: I don't see them. Perhaps you have posted in the wrong thread.In summary, the problem involves a student kicking a puck up an inclined plane with an initial speed v_0. The plane has an angle of inclination \theta and a coefficient of friction \mu. The relevant equations are F_x=m\ddot r and F_y=0, where F_x is the sum of forces in the x-direction and F_y is the sum of forces in the y-direction. The equations need to be modified to include the friction force and the normal force, which are dependent on the coefficient of friction and the angle of inclination. The spring constants do not play a role in this problem.
  • #1
pizza_dude
7
0
1. Homework Statement
A student kicks a puck with initial speed [itex] v_0 [/itex] so that it slides straight up a plane that is inclined at an angle [itex] \theta [/itex] above the horizontal. the incline has a coefficient of friction (both static and kinetic) of [itex] \mu [/itex]
Write down Newton's second law for the puck and solve it to give it's position as a function of time.

2. Homework Equations
[itex] F=m\ddot r [/itex]

The Attempt at a Solution


idk why I am having such a hard time with this. imagine pucked is kicked diagonally up and to the right. that incline will be the positive x-axis with angle [itex] \theta [/itex] to the horizontal.
forces
1. friction: -x direction
2. normal: positive y axis
3. gravity: straight down(component of x and y)
4. [itex] v_0 [/itex]: positive x direction

[itex] F_x=m\ddot r [/itex]
[itex] \vec F_g \sin\theta + v_0 -\mu_x = m\ddot x [/itex]

[itex] F_y=0 [/itex]
[itex] \vec N - \mu_y + \vec F_g\cos\theta=0 [/itex]

thats as far as I've gotten. are these equations correctly written?

thanks
 
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  • #2
pizza_dude said:
A student kicks a puck with initial speed [itex] v_0 [/itex] so that it slides straight up a plane
pizza_dude said:
imagine pucked is kicked diagonally up and to the right.
As I understand it, the bold part of the first quote means that the puck is not kicked diagonally up the plane.
 
  • #3
Nathanael said:
As I understand it, the bold part of the first quote means that the puck is not kicked diagonally up the plane.

after that it says it's an inclined plane.
 
  • #4
pizza_dude said:
after that it says it's an inclined plane.
Sorry, I thought you were thinking the puck was moving diagonally up the inclined plane instead of straight up the inclined plane.

Your equations aren't correct but it's hard to give you any guidance since you didn't explain them. Perhaps you could start by explaining what you mean by [itex]\mu_x[/itex]and [itex]\mu_y[/itex]?
[itex]\mu[/itex] is the coefficient of friction, a scalar, it doesn't have x and y components.
 
  • #5
pizza_dude said:
##\vec F_g \sin\theta + v_0 -\mu_x = m\ddot x##
Apart from the question Nathanael asked of what ##\mu_x ## is supposed to be, the ##v_0## makes no sense there. You can't add a force to a velocity.
 
  • #6
okay...so taking out the [itex] v_0 \text { and } \mu_x , \mu_y [/itex] the equations are correct? but how do the spring constants come into play?
 
  • #7
pizza_dude said:
okay...so taking out the [itex] v_0 \text { and } \mu_x , \mu_y [/itex] the equations are correct? but how do the spring constants come into play?
You can't just throw them away. You need to replace them with the correct terms, involving friction.
Where have spring constants been mentioned in this thread?
 

Related to How Does Friction Affect a Puck Sliding Up an Inclined Plane?

1. What is the relationship between the mass of the puck and its acceleration on an incline?

The mass of the puck has no direct effect on its acceleration on an incline. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Therefore, the mass of the puck does not affect its acceleration on an incline, but the net force acting on it does.

2. How does the angle of the incline affect the acceleration of the puck?

The angle of the incline affects the acceleration of the puck by changing the component of the force acting on the puck along the incline. As the angle of the incline increases, the component of the force acting on the puck along the incline decreases, resulting in a slower acceleration. This can be explained by the trigonometric relationship between the force and the angle of the incline.

3. What is the difference between static and kinetic friction in the context of a puck on an incline?

Static friction is the force that prevents an object from moving when a force is applied to it, while kinetic friction is the force that opposes the motion of an object. In the context of a puck on an incline, static friction will keep the puck from sliding down the incline until the force applied to it is greater than the maximum value of static friction. Once the force is greater, kinetic friction will come into play and resist the motion of the puck down the incline.

4. How does the coefficient of friction affect the motion of the puck on an incline?

The coefficient of friction is a measure of the frictional force between two surfaces. In the context of a puck on an incline, a higher coefficient of friction means that there is a greater resistance to motion, resulting in a slower acceleration. On the other hand, a lower coefficient of friction means there is less resistance to motion, resulting in a faster acceleration.

5. What is the role of gravity in the motion of a puck on an incline?

Gravity is the force that pulls the puck down the incline. In the absence of any other forces, the puck would accelerate down the incline at a rate of 9.8 m/s², according to the acceleration due to gravity on Earth. However, in the presence of other forces, such as friction, gravity can be counteracted and affect the acceleration of the puck on the incline.

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