- #1
24forChromium
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Homework Statement
A wheel spins in outer space, it is in the shape of a ring (negligible thickness) with a radius of 1 meter and a mass of 1 kilogram, it is spining at π Radian/sec around its central axis (z-axis) in a fashion that is like any other car wheel. Just then, an impulse of 10N*sec was applied on its left side with a direction pointing straight up (z). What are the components of the final angular momentum?
(There's a picture. Hopefully the picture works)
Homework Equations
Moment of inertia = mass * radius
angular acceleration = torque / angular inertia
torque = lever arm length * force
The Attempt at a Solution
First, the impulse causes an angular impulse on the ring, sadly I don't know how to convert N*sec to meter*kilogram*Radian/sec, if that's what angular impulse look like at all. Then, this angular impulse creates a new component of angular momentum in the y-axis, and at last, add the original angular momentum with the new angular momentum, use pythagorean theorem and trignometry to calculate the final angular momentum.