- #1
anonymous99
- 25
- 5
- Homework Statement
- I understand if we take the face atom, there's 4 atoms in the same plane and 4 behind and 4 in front to give 12 but when I try to do the same for the corner atom, I can see it's touching the face atom and 2 other corner atoms in the same cell. Since corner atoms are shared by 8 squares, shouldn't this sum to 24?
- Relevant Equations
- Picture is attached to show what I mean. Look at the bottom left corner of the grey square in the unit cell on the left. It has 12 neighbours from the plane it lies on, 3 more from the grey square and 9 more from the 3 omitted squares. What mistake am I making?
Edit: nevermind, I realized my mistake. Corner atoms don't touch in FCC, so there's just 4 neighbours in each plane which sums to 12.