- #1
jigglywiggly
- 4
- 0
So like say you have (AlK(SO4)2•12H2O)
And then how does the reaction go?
Is it like (AlK(SO4)2•12H2O) -> AlOH + H2SO4 or something like this?
Was also wondering how like
(NaCH3COO) would work with H2O as well...
same for this
(Cu(NO3)2•2.5H2O)
These are acid-base, and I am pretty new to them, could I get some clarifications? Thanks
And then how does the reaction go?
Is it like (AlK(SO4)2•12H2O) -> AlOH + H2SO4 or something like this?
Was also wondering how like
(NaCH3COO) would work with H2O as well...
same for this
(Cu(NO3)2•2.5H2O)
These are acid-base, and I am pretty new to them, could I get some clarifications? Thanks