- #1
clavin
- 11
- 0
well first i saw this solution of a zener diode problem on net
A 5.0v stabilised power supply is required from a 12v d.c. input source. The maximum power rating of the Zener diode is 2W. Load resistance = 1 kiloohm Using the circuit above calculate:
circuit : http://www.electronics-tutorials.ws/diode/diode24.gif
b) The value of the series resistor, RS
12-5/(400mA) = 17.5 ohm
so is the above solution right
cuz i think it should be
12-5/(405mA)
second can somebody explain me a bit about ce transistor circuits
first a little bit about what it does
and secondly how does the circuit works
like why there's grounding
and also i saw that the emitter is connected to the positive terminal of one battery and the negative terminal of other
so in that branch how will the current flow
from postitve terminal of one batter to the negative of the other without passing through emitter? or in some other way
A 5.0v stabilised power supply is required from a 12v d.c. input source. The maximum power rating of the Zener diode is 2W. Load resistance = 1 kiloohm Using the circuit above calculate:
circuit : http://www.electronics-tutorials.ws/diode/diode24.gif
b) The value of the series resistor, RS
12-5/(400mA) = 17.5 ohm
so is the above solution right
cuz i think it should be
12-5/(405mA)
second can somebody explain me a bit about ce transistor circuits
first a little bit about what it does
and secondly how does the circuit works
like why there's grounding
and also i saw that the emitter is connected to the positive terminal of one battery and the negative terminal of other
so in that branch how will the current flow
from postitve terminal of one batter to the negative of the other without passing through emitter? or in some other way