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Homework Statement
A 245 kg motorcyle & rider can produce an acceleration of 3.50 m/s sq while traveling at 25 m/s. At that speed, the forces resisting motion (friction & air) total 400 N. What force does the motorcycle exert backward to produce it's acceleration?
Homework Equations
Force = mass x acceleration + Friction motion
The Attempt at a Solution
Fnet = (m x a) + Ffr
= (245 x 3.5) + 400N
= 1257.5N
This needs a 2nd look. I'm not sure if the speed matters since we have mass and acceleration values. Please take a look, I'll stand by.