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mlostrac
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Homework Statement
A heat engine operates between 40°C and 380°C. Being a real engine, its
efficiency is only 60% of that theoretically possible for a Carnot engine at these
temperatures. If it absorbs heat at a rate of 60 kW, at what rate does it exhaust
heat?
Homework Equations
e = 1 - TL/TH --> Carnot Efficiency
e = 1 - QL/QH --> Efficiency
The Attempt at a Solution
1) First I changed the temperatures to Kelvins, then I calculated the Carnot efficiency:
e = 1 - (313/657)
= 1 - 0.48
= 0.52
2) Then I determined the actual efficiency to be:
0.52 x 0.60 = 0.31 or 31%
3) Finally I plugged in the efficiency in 2 to the 2nd equation above:
0.31 = 1 - (QL/60 kW)
60(0.31) = 60 - QL
18.72 = 60 - QL
QL = 41.3 kW
So therefore the engine exhausts heat at 41.3 kW or 41.3 kJ/s. I think I did this right, but I'm the type of guy who always manages to forget something or other.
Does this look right?