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eliassiguenza
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String Problem! Please Help!
A 54 g ice cube can slide without friction up and down a 35 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 12 cm. The spring constant is 27 N/m
F = -kx
F = ma
soh cah toa
PE = -1/2 kx^2 = 1/2 mv ^2
x = Vt+1/2at^2
I did the following and I got it wrong .. any ideas?
F= k * x
PE = 1/2 k * x^2 = m*v^2
V^2 = P.E./(1/2 * m) = Square Root of that to get V.
mass * cos of angle = to find the force keeping the block of ice on the ground.
mass * sin of angle = to find the parallel force, which pulls on the ground ...
- Parallel Force/ mass = acceleration of the ice block.
using Kinematic equations I determined the time it'll take to do the whole thing... without the spring anymore just to go up and down where it started..
I divided that time because it obviously plots a parabola... and that's when it stops to come back.. that value of time i used in... V t + 1/2 at^2 to find distance ... but
i got it wrong .. any ideas?
Homework Statement
A 54 g ice cube can slide without friction up and down a 35 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 12 cm. The spring constant is 27 N/m
Homework Equations
F = -kx
F = ma
soh cah toa
PE = -1/2 kx^2 = 1/2 mv ^2
x = Vt+1/2at^2
The Attempt at a Solution
I did the following and I got it wrong .. any ideas?
F= k * x
PE = 1/2 k * x^2 = m*v^2
V^2 = P.E./(1/2 * m) = Square Root of that to get V.
mass * cos of angle = to find the force keeping the block of ice on the ground.
mass * sin of angle = to find the parallel force, which pulls on the ground ...
- Parallel Force/ mass = acceleration of the ice block.
using Kinematic equations I determined the time it'll take to do the whole thing... without the spring anymore just to go up and down where it started..
I divided that time because it obviously plots a parabola... and that's when it stops to come back.. that value of time i used in... V t + 1/2 at^2 to find distance ... but
i got it wrong .. any ideas?