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mmmboh
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[PLAIN]http://img688.imageshack.us/img688/3941/fingernorm.jpg
Because the cone is being held up, I said mg=2fy, where f is the friction force, so mg=2uNcos(x) (where x=theta), and I got N=mg/(2ucos(x)).
The cone also isn't moving from side to side, so I said Nx=fx, so fsin(x)= uNsin(x)=Ncos(x), so u=cot(x), then I replace u in my first equation to get N=mg*tan(x)/(2cos(x))...
I have a feeling this is wrong though. Help please.
Because the cone is being held up, I said mg=2fy, where f is the friction force, so mg=2uNcos(x) (where x=theta), and I got N=mg/(2ucos(x)).
The cone also isn't moving from side to side, so I said Nx=fx, so fsin(x)= uNsin(x)=Ncos(x), so u=cot(x), then I replace u in my first equation to get N=mg*tan(x)/(2cos(x))...
I have a feeling this is wrong though. Help please.
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