Q: What number is a whole number can be divisible by 5 and 7 and when divided by 9 the remainder is 6?

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It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

Any number is divisible by any number. There is no number that is divisible by any number into a whole number with no remainder other than 0.

divisible

"Divisible by" means that you can carry out the division, and that you'll get a whole number. Or, if you use whole number division, that there will be no remainder. For example: 8 divided by 2 = 4, remainder zero. 8 is divisible by 2. On the other hand, 9 divided by 2 = 4, remainder 1 (on a calculator, you get decimals: 4.5). That means that 9 is not divisible by 2.

416 divided by 4 equals 104, a whole number. Since there is no remainder, we know that 416 is divisible by 4.

301

A number is divisible by 9 if a whole number of 9s can go into it and leave no remainder.

Try dividing the number by 19. If the answer is a whole number (with no remainder), then the number is divisible by 19.

When we say that a number is divisible by five , we mean that : 1.The number when divided by five has a quotient in whole number , and 2.No remainder if left after the division. Since 2 divided by five results in the quotient as 0.4 (which is not a whole number), we say that 2 is not divisible by five . (Even though the remainder becomes zero , if we carry on the division after putting the decimal sign in the quotient.)

Of course it is. Any number can be divided by another number (the result in this case is not an integer (whole number)) 753248 / 11 = 68477,0909... or 68477 1/11 (There is a remainder of 1) -------------------------------------------------------------------------------------------------------------- Given the nature of the question the answer is no - assuming that the definition of divisible is that no remainder is left.

12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.

2346.6667

0.6667

A factor.

No, if you have a remainder larger than your whole number, you must have divided incorrectly. very good

no because if u divide a number by three u will get a remainder

1323 divided by 2 equals 661.5a number X is said to be divisible by another number Y only when the remainder is 0 and quotient is a whole number.2 is not a divisible of 1323 or 1323 is not divisible by 2

266 / 2 = 133 remainder 0

1098765433 will have a remainder of 1.

Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7

6

The meaning of "can be divided by" has lost a bit of its precision, since (with the exception of zero) anything can be divided by anything. Some people use it interchangeably with "divisible," which in mathematics means that there will be no remainder. Example: 20 can be divided by 8. The answer is 2.5 20 is not divisible by eight since the answer isn't a whole number. 20 can be divided by 10. The answer is 2. 20 is divisible by 10 since there isn't a remainder.

8

23. There are many others. Any number larger than 7 that is not directly divisible by 7 will have a remainder, for example, 8 / 7 = 1 remainder 1, 9 / 7 = 1 remainder 2. But 14, 21, 28 etc, which are all directly divisible by 7, all have whole numbers as an answer (no remainders).

Because you can subtract a whole number of sevens from 2275 and not leave a remainder. That is one definition of "divisible".

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