How Do You Differentiate e^(A*t) When A is a Constant Operator?

In summary, the problem asks to calculate the derivative of e^{\hat{A}t} where \hat{A} is an operator that does not explicitly depend on t. The solution involves using the chain rule and results in \frac{d}{dt}e^{\hat{A}t} = (\frac{d}{dt}(\hat{A})t + \hat{A})e^{\hat{A}t}, with the final result depending on whether the operator is bounded or not.
  • #1
sunrah
199
22

Homework Statement


calculate [itex]\frac{d}{dt}e^{\hat{A}t}[/itex] where [itex]\hat{A} \neq \hat{A}(t)[/itex] in other words operator A doesn't depend explicitly on t.

Homework Equations



The Attempt at a Solution



[itex]\frac{d}{dt}e^{\hat{A}t} = (\frac{d}{dt}(\hat{A})t + \hat{A})e^{\hat{A}t} = (\sum^{n}_{i=0}\frac{d\hat{A}}{dx_{i}}\frac{dx_{i}}{dt}t + \hat{A})e^{\hat{A}t} [/itex]

if the xi ≠ xi(t) we get [itex]\hat{A}e^{\hat{A}t} [/itex]

but is this correct I know how to define the derivative of an operator if it is explicitly dependent on the variable of differentiation but not in this case.
 
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  • #2
First off are you sure this isn't just a partial differntiation in which case there is no problem. Otherwise this looks quite allright.
 
  • #3
sunrah said:

Homework Statement


calculate [itex]\frac{d}{dt}e^{\hat{A}t}[/itex] where [itex]\hat{A} \neq \hat{A}(t)[/itex] in other words operator A doesn't depend explicitly on t.

Homework Equations



The Attempt at a Solution



[itex]\frac{d}{dt}e^{\hat{A}t} = (\frac{d}{dt}(\hat{A})t + \hat{A})e^{\hat{A}t} = (\sum^{n}_{i=0}\frac{d\hat{A}}{dx_{i}}\frac{dx_{i}}{dt}t + \hat{A})e^{\hat{A}t} [/itex]

if the xi ≠ xi(t) we get [itex]\hat{A}e^{\hat{A}t} [/itex]

but is this correct I know how to define the derivative of an operator if it is explicitly dependent on the variable of differentiation but not in this case.

Yup, there's nothing wrong with your solution.
 
  • #4
It makes a world of difference if the operator in the exponent is bounded or not. Either way, there's a strict definition of such a derivative in terms of limits which can be found in almost all books on functional analysis.
 
  • #5


Yes, your approach is correct. When the operator A does not depend explicitly on t, it can be treated as a constant and the derivative of e^{\hat{A}t} is simply \hat{A}e^{\hat{A}t}. This can also be seen by using the definition of the derivative as a limit and noting that the limit of a constant is just the constant itself.
 

Related to How Do You Differentiate e^(A*t) When A is a Constant Operator?

What is the definition of the derivative of an operator?

The derivative of an operator is a mathematical concept that represents the rate of change of an operator with respect to its variable. It is similar to the derivative of a function, but instead of measuring the change in output for a change in input, it measures the change in output operator for a change in the variable of the operator.

Why is the derivative of an operator important?

The derivative of an operator is important because it allows us to analyze the behavior of operators and their effects on functions. It helps us understand how small changes in the operator's variable can affect the overall output of the operator. This is crucial in many areas of mathematics and physics, such as differential equations and quantum mechanics.

How is the derivative of an operator calculated?

The derivative of an operator is calculated using the same rules as the derivative of a function, such as the power rule, product rule, and chain rule. However, the main difference is that the variable in the derivative notation is replaced with the operator, and the derivative is taken with respect to the variable of the operator.

Can the derivative of an operator be negative?

Yes, the derivative of an operator can be negative. This means that the operator is decreasing as the variable increases. It is also possible for the derivative to be positive, which indicates that the operator is increasing as the variable increases. The sign of the derivative depends on the behavior of the operator and its variable.

Are there any applications of the derivative of an operator?

Yes, there are many applications of the derivative of an operator in various fields of mathematics and physics. For example, in quantum mechanics, the derivative of an operator is used to determine the rate of change of a particle's wave function. In economics, it is used to analyze the effects of different variables on a system. In general, the derivative of an operator helps us understand the behavior and properties of various systems and functions.

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