- #1
lemon
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1. Calculate the total moment of the forces on the thin beam shown in the attached file, about each of the points A, B, C, D, E.
Each of the distances AB, BC, CD, DE is 1m.
2.Clockwise moments = Anit-clockwise moments
3.(Axd)+(Exd)+[50sin(45)]=(20xd)+25
20+20+42.5=20+25
82.5=45
=37.5N in the upwards direction
There is also a force of 50cos(45)+5N=26.3+5=31.3N to the right
I have a sinking feeling about my method here
Please advise?
Each of the distances AB, BC, CD, DE is 1m.
2.Clockwise moments = Anit-clockwise moments
3.(Axd)+(Exd)+[50sin(45)]=(20xd)+25
20+20+42.5=20+25
82.5=45
=37.5N in the upwards direction
There is also a force of 50cos(45)+5N=26.3+5=31.3N to the right
I have a sinking feeling about my method here
Please advise?