- #1
tempneff
- 85
- 3
Hi all, I am forced to step outside of my field to investigate a problem that might root in sublimation of solids. I am trying to calculate the mass (after a certain time) of a material that we know is sublimating at , say .000123 g/(cm^2 hr). Is it as simple as multiplying the rate by the initial surface area and time?
Subliming for 20 cm^2 solid for 1000 hrs: mass = .000123*20*1000 = 2.46 grams of material turned to gas?
Seems to me that since the surface area is changing I have to integrate. Am I making it too complicated?
Note: (Consider the solid in vacuum and isothermal and the sublimation rate is for this environment)
Subliming for 20 cm^2 solid for 1000 hrs: mass = .000123*20*1000 = 2.46 grams of material turned to gas?
Seems to me that since the surface area is changing I have to integrate. Am I making it too complicated?
Note: (Consider the solid in vacuum and isothermal and the sublimation rate is for this environment)
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