How Do You Calculate Mass and Acceleration in a Spring Mass System?

[Ahmad786]

Homework Statement

An object suspended from a spring with a spring constant of 2.56 N/m vibrates with a frequency of 0.148 Hz
a. What is the mass of the object
b. What is the acceleration of the object at a displacement of -0.120m from the equilibriam position

Homework Equations

a. T=2pi[tex]\sqrt{}m/k[/tex] m=Tk/4pi²' T=1/f
b. a=-kx/m ?

The Attempt at a Solution

a.T=1/f T=1/0.148Hz T=6.756756757s m=Tk/4pi²' m=(6.756756757s)(2.56N/m)/4pi²' m=2.96kg ---- I do not understand if this is right and I think I made a mistake ----
b. I can't figure out what equation to use and how to manipulate it to get an equation for acceleration for the condition

 

[ideasrule]

a. It's right.
b. It's a=-kx/m.

 

[kerimek]

given.

I would like to clarify that the given information is not enough to accurately calculate the mass and acceleration of the object in the spring mass system. To accurately determine the mass of the object, we would need to know the period of oscillation, which is not provided in the given statement. The equation used to calculate mass (m=Tk/4pi2) requires the period (T) and the spring constant (k), both of which are not given. Therefore, the calculated mass of 2.96kg cannot be considered accurate.

Similarly, to calculate the acceleration at a specific displacement, we would need to know the amplitude of the oscillation and the initial conditions of the system. The equation used to calculate acceleration (a=-kx/m) requires the displacement (x), spring constant (k), and mass (m), all of which are not provided in the given statement. Therefore, it is not possible to accurately determine the acceleration at a displacement of -0.120m from the equilibrium position.

In order to accurately calculate the mass and acceleration of the object in this spring mass system, we would need more information such as the period, amplitude, and initial conditions of the system. Without this information, any calculated values would be approximations and cannot be considered accurate.