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huybinhs
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Homework Statement
The graph is:
http://i995.photobucket.com/albums/af79/huybinhs/Lastproblem.gif
A particle moves along the x-axis. The velocity of this particle as a function of time is shown in the figure. Assume the particle is located at x = 0 m at time t = 0 s.
1. What is the acceleration of the particle at time t = 26.0 s?
2. What is the position of the particle along the x-axis at time t = 26.0 s?
3. What is the net displacement of the particle between time t = 4.0 s and t = 38.0 s?
Homework Equations
x = x0 + v0t + 1/2 at2
v = v0 + at
2(x-x0) = (v+v0)t
v^2 = v^02 + 2a(x − x0)
g = 9.8 m/s^2
The Attempt at a Solution
1. - 0.3 m/s² ANS {by slope of graph at t = 26.0} => incorrect answer.
2. x = (-2)(26) + (0.5)(-0.3)(26)² = -52 - 101.4 = -153.4 ANS => incorrect answer.
{use eq for x at t = 26}
3. - 7.5 m ANS {by area under graph from t = 4 to t = 38} => incorrect answer.
Please help! Thanks!