Puzzle: Who Pays More in the Beer Hall?

  • Thread starter quartodeciman
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    Beer Puzzle
In summary, eleven friends went to a beer hall and split into two tables, A and B. Each person ordered one round for their own table. Despite table A having more payers, a person at table A ends up paying more than a person at table B. This is because the guys at table A ordered more expensive drinks and the guys at table B ran off without paying. Another possibility is that the waiter missed the order from table B and they left in frustration. Some people struggle with this puzzle because they assume the tables are ordering and drinking at the same pace, but the key is that table A has more payers.
  • #1
quartodeciman
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This story surprisingly puzzles some people:

Eleven friends go into a beer hall. Six of them sit at table A and five of them sit at table B. Each of the eleven orders one round for his own table. Now table A has more payers, but a person at table A ends up paying more than a person at table B.

?
 
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  • #2
The guys at table A ordered more expensive drinks, where's the brain teaser?
 
  • #3
Chen said:
The guys at table A ordered more expensive drinks, where's the brain teaser?

NO!
The guys on B run off from the bill.

Another is that the waiter didn't catch the order from the guys around B, and, in frustration, they left to see "Van Helsing" instead.
 
  • #4
quartodeciman said:
This story surprisingly puzzles some people:

Eleven friends go into a beer hall. Six of them sit at table A and five of them sit at table B. Each of the eleven orders one round for his own table. Now table A has more payers, but a person at table A ends up paying more than a person at table B.

?

Sure, why shouldn't he. Each guy on table A pays for 6 drinks while each dude at B pays for only 5.

This is true if all drinks cost the same and the waiter was a patient, vampire fearing man.

Whassamattah ?
 
  • #5
People who fail this test end up hopeless drunks.

(What seems to throw some people off is that table A is consuming more beer than table B)
:smile:
 
  • #6
Oh dear..
(Besides, "Van Helsing" was an atrociously bad movie..)
 
  • #7
Gokul43201 said:
Sure, why shouldn't he. Each guy on table A pays for 6 drinks while each dude at B pays for only 5.

This is true if all drinks cost the same and the waiter was a patient, vampire fearing man.

Whassamattah ?

That's why a wise person buys a pitcher for a group, not individual drinks :biggrin:
 
  • #8
Table A people all pay more, but also get more beer.

Table A people buy 6 beers and drink 6 beers.

Table B people buy 5 beers and drink 5 beers.

Very easy if you haven't been drinking a lot.

Njorl
 
  • #9
it is really strange how come so many people here are stupid enough to not be able to solve this problem.
 
  • #10
I suspect that many people at first assume (without warrant) that the two table-fulls are somehow ordering and drinking in complete synchrony.

It is probably important to emphasize that table A has more payers (without drawing attention to more drinks ordered) to pull this puzzle off.
 

1. How do you determine who pays more in the beer hall?

The puzzle involves using a mathematical equation to calculate the cost of each person's beer order and determining who has the higher cost.

2. What factors are taken into account when solving the puzzle?

The puzzle takes into account the cost of each person's beer order, the number of people at the table, and the percentage of tax and tip added to the total cost.

3. Can the puzzle be solved without using math?

No, the puzzle requires the use of mathematical equations to accurately calculate the cost of each person's beer order.

4. Is there a specific formula to solve the puzzle?

Yes, the formula is [(cost of beer order * (1 + (tax percentage/100)) * (1 + (tip percentage/100))] / number of people.

5. Are there any tricks or shortcuts to solving the puzzle?

Yes, you can simplify the formula by factoring out the common term (1 + (tax percentage/100)) and (1 + (tip percentage/100)) to make it easier to solve.

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